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49m^2+7m-20=0
a = 49; b = 7; c = -20;
Δ = b2-4ac
Δ = 72-4·49·(-20)
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3969}=63$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-63}{2*49}=\frac{-70}{98} =-5/7 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+63}{2*49}=\frac{56}{98} =4/7 $
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